00:01
Here we have a uniform electric field with a constant value of 4 .0 times 10 to the 3 volts per meter directionally downward.
00:09
This is a uniform field.
00:11
And at point p, it's measured that the potential, the electric potential, is 155 volts.
00:17
And we're asked first to find what is the electric potential at a point 6 .0 times 10 to the 3 meters directly above p.
00:24
So our potential difference here, we can find with the relation that electric field, is equal to potential difference divided by distance.
00:39
So in our first case for a, d is equal to 6 .0 times 10 to minus 3 meters.
00:48
And then our potential difference, delta v is equal to our electric fields, multiply this distance.
00:58
So our delta v here is equal to 24 volts.
01:06
And since it's the electric field is downwards.
01:10
There are two ways to think about this, one just geometrically.
01:13
The field is downwards.
01:14
If you move up, you're going to have a higher voltage...