Question
An electric motor contains a 250 -turn circular coil $5.4 \mathrm{~cm}$ in diameter. If it develops a maximum torque of $2.0 \mathrm{~N} \cdot \mathrm{m}$ at a current of $3.1 \mathrm{~A}$, what's the magnetic field strength?
Step 1
The number of turns of the coil is $n = 250$ turns, the diameter of the coil is $d = 5.4$ cm which is equal to $5.4 \times 10^{-2}$ m, the current in the coil is $I = 3.1$ A, and the maximum torque is $\tau = 2$ Nm. Show more…
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