An electric motor takes 5.0 A from a 110 V line. Determine the power input and the energy, in J

step 1 in the given problem current drawn by the electric motor is given as i is equal to 5 .0 and the

An electric motor takes 5.0 A from a 110 V line. Determine...

An electric motor takes $5.0$ A from a $110 \mathrm{~V}$ line. Determine the power input and the energy, in $\mathrm{J}$ and $\mathrm{kW} \cdot \mathrm{h}$, supplied to the motor in $2.0 \mathrm{~h}$. $$ \begin{aligned} \text { Power } &=\mathrm{P}=V I=(110 \mathrm{~V})(5.0 \mathrm{~A})=0.55 \mathrm{~kW} \\ \text { Energy } &=\mathrm{P} t=(550 \mathrm{~W})(7200 \mathrm{~s})=4.0 \mathrm{MJ} \\ &=(0.55 \mathrm{~kW})(2.0 \mathrm{~h})=1.1 \mathrm{~kW} \cdot \mathrm{h} \end{aligned} $$

An electric motor takes $5.0$ A from a $110 \mathrm{~V}$ line. Determine the power input and the energy, in $\mathrm{J}$ and $\mathrm{kW} \cdot \mathrm{h}$, supplied to the motor in $2.0 \mathrm{~h}$.
$$
\begin{aligned}
\text { Power } &=\mathrm{P}=V I=(110 \mathrm{~V})(5.0 \mathrm{~A})=0.55 \mathrm{~kW} \\
\text { Energy } &=\mathrm{P} t=(550 \mathrm{~W})(7200 \mathrm{~s})=4.0 \mathrm{MJ} \\
&=(0.55 \mathrm{~kW})(2.0 \mathrm{~h})=1.1 \mathrm{~kW} \cdot \mathrm{h}
\end{aligned}
$$

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Key Concepts

Electric Power

Electric power is the rate at which electrical energy is transferred by an electric circuit. It is calculated as the product of voltage and current. This concept is fundamental in electrical engineering and physics, as it quantifies how much work an electric system can perform over time and is often expressed in Watts or kilowatts.

Electric Energy

Electric energy is the amount of work done, or energy transferred, by an electric current over a period of time. It is determined by multiplying power by time, linking the instantaneous work rate to the total energy expended. Understanding electric energy is crucial for analyzing energy consumption and efficiency in electrical systems.

Unit Conversion

Unit conversion involves changing measurements from one unit system to another to maintain consistency in calculations. In the context of electric power and energy, it is common to convert units such as watts to kilowatts, joules to megajoules, and seconds to hours or kilowatt-hours, ensuring that formulas and results are correctly interpreted across different scales and standards.

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