Question
An electrolyzer passes electric current through water, dissociating some of the water molecules and thus producing hydrogen $\left(\mathrm{H}_{2}\right)$ and oxygen $\left(\mathrm{O}_{2}\right)$ gas. Electrolyzers powered by renewable wind and solar energy sources could produce hydrogen for fuel-cell vehicles. In an experimental electrolyzer, current flows through a cylindrical tube of diameter $6.85 \mathrm{~cm}$. The tube contains an alkaline solution that decreases the resistivity to $0.0466 \Omega \cdot \mathrm{m}$. If the tube carries $18.7 \mathrm{~A}$, what are (a) the current density and (b) the electric field in the solution?
Step 1
The radius is half of the diameter, so we have: \[ r = \frac{d}{2} = \frac{6.85}{2} = 3.425 \, \text{cm} \] Then, we convert it to meters by multiplying by \(10^{-2}\): \[ r = 3.425 \times 10^{-2} \, \text{m} \] Show more…
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