00:01
Okay, so problem 28 .8, you have an electron of proton that are each moving at a certain speed in perpendicular paths that's shown.
00:08
And at the instant that they are at these positions, we're supposed to find the magnitude direction of the total magnetic field they produce at the origin to start.
00:16
Okay, so first off, we're going to start off with the electron.
00:22
We have the magnetic field, and that's going to be due to a moving point charge.
00:30
So that's going to be mu not over 4 pi.
00:37
And then we have q, the charge of the electron.
00:41
And i write down down as negative.
00:44
And then we have the distance squared.
00:46
So that's 5 nanometers squared.
00:52
And then we have the velocity.
00:54
And that's the cross product of the velocity with the r vector.
00:59
So that's going to be this r vector here.
01:06
It's from the point to the point where the charge is to the point at the origin, that straight line down.
01:12
So then we have the velocity, which just had the number, the magnitude, and we have the direction for the velocity is negative i -hat.
01:22
That's to the left, so negative i -hat, cross -product with the vertically down vector, so that's negative j -hat.
01:33
Okay, and so what we're left with is numbers up to the point where we have a cross -product.
01:37
Product and so that's going to come out to a negative 0 .5 milatessla and the i -hat negative i -hat cross negative j hat comes out to be k -hat so then we can rewrite this as 0 .5 milat tesla in negative k -hat direction so at the origin this produces the magnetic field vector into the page.
02:06
Okay now for the proton we do the same thing.
02:11
What's different is we have a different distance, and we have different cross product.
02:19
So i'll write down this qe this time for positive.
02:21
That's the charge of a proton over four nanometers squared.
02:30
The velocity is the same, 735.
02:33
And then we have that as the velocity vector.
02:38
The direction is down, so negative j hat.
02:40
And then the r vector this time is in towards the origin.
02:46
So it's going to cross product with negative i hat.
02:51
And this is going to be negative j hat across the negative i hat.
02:54
This is going to be negative k hat.
02:56
So again, we're going to have a positive number out front like we have here, but then negative k hat.
03:03
So that's going to be 0 .7.
03:08
I'm glitching here.
03:10
0 .736.
03:16
Again, i'm getting some glitch in here, 0 .7 .436 mil -tesla and a negative k -hat direction.
03:30
Okay, and then we can add these together.
03:32
So then in all, this would be 1 .236 miltessla in the negative k hat direction.
03:49
Okay, so b, the magfield of the electron, this is at the location of the proton.
03:55
So it's a little different.
03:57
We have to find the magnetic field that the election causes at an angle.
04:02
It's not straight perpendicular to its velocity.
04:07
So this time it's an angle back to the proton.
04:11
So that's going to change our cross part a little bit.
04:14
So what we need to do is we need to just start all by writing down with the magnet field of moving charges.
04:21
So that's going to be a magnet field.
04:24
Fuel is going to be mu not over 4 pi, same as before, electron charge.
04:34
And we have over the distance squared.
04:41
So what's this distance squared? so that's going to be, let's see, pythagorean theorem.
04:48
So we have 5 squared plus 4 squared equals 41 squared.
04:58
Square, 41.
05:00
So then we can write is we write 41.
05:05
And let's distinguish 41 nanometer squared between the other 41 nanometer square.
05:11
In this case, we only are squaring the units themselves...