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An electron has a momentum with magnitude three times the magnitude of its classical momentum. (a) Find the speed of the electron. (b) How would your result change if the particle were a proton?
a) 0.943$c$
b) same
Numerade Educator
University of Washington
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Hope College
Well, the momentum of electron is three times the magnitude of its classical mental. So relax, mystic momentum. Uh, relativistic momentum is equal to three times of classical movement, too. Three times off, plaster momentum. And we know that. Relax, mystic momentum is am not times we divided by square root off one minus we squared, divided by C squared. This is the creation for Lazarus. The momentum on this is equal to three times classical momentum on Blasco. Momentum is just am not times we and not gets cancelled from both sides. And, uh, then taking square we have we square divided by one minus re squared, divided by C square is equal to mine times we square. Let's divide BC greeted by the square, Then we have one divided by one minus. We squared. Divided by C square is equal to nine. No cross multiplying. We have one One is equal to mine. Minus mine. We squared, divided by C square. Actually, we need to find a degree speed. Well, uh, further simplifying. We have one minus. Mine is equal to minus 93 squared, divided by C square and one minus minus minus eight minus eight Is equal to minus mine. We squared, divided by C square, and we square is equal to ah 0.8 times See, script minus gets cancelled from both sides and re speed off electronics equal to 0.94 three times the speed of light and part B Well, the result would remain The scene, uh, result would remain the same for any particle result would remain the same for any particle, any particle because I must gets cancelled up.