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# An electron has an initial velocity of $5.00 \times 10^{6} \mathrm{m} / \mathrm{s}$ in a uniform $2.00 \times 10^{5} \mathrm{N} / \mathrm{C}$ strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? (b) How far does the electron travel before coming to rest? (c) How long does it take the electron to come to rest? (d) What is the electron's velocity when it returns to its starting point?

## a) $\vec{E}$ is directed in $\vec{v}_{i}$b) $d=3.56 \cdot 10^{-4} \mathrm{m}$c) $t=1.42 \cdot 10^{-10} \mathrm{s}$d) $\overrightarrow{v_{j}}=-\overrightarrow{v_{i}}=-5 \cdot 10^{6} \frac{\mathrm{m}}{\mathrm{s}}$

#### Topics

Electric Charge and Electric Field

### Discussion

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##### Marshall S.

University of Washington

##### Aspen F.

University of Sheffield

##### Jared E.

University of Winnipeg

### Video Transcript

find. So we need to first find the the direction of the left. 13 on the questions is that it's slowing it down. Great. So that means that the force on Electron has to be in love with the direction. Pretend it's the electron. The electric field is actually in the direction off its velocity, self trained, that town, the force and hence a good Nisa letter, the simulated only in the force of the law of the direction just possible of the electric field and its direction of velocity day that Sylvia Bar E. But Lee's given that the initial velocity is fine for six me does plus second Theo June of the final velocity has to Museo Andi also this very standard we know you worked for accelerations e que late and just using the total equation of action movie squares you scrape plus two years we can see no equals. Just plugging in the values Not pretty straightforward. And we just take the negative sign because the initial velocity and acceleration are, you know, using directions A which is each jewel with em into s, which is what we need to find great. So far, it s basically becomes training you to stand for 12 in knife cheaper and a minus two would don't into 10. That's 5 to 1.6. That's time T O b. So I see. You know, I need to find the diamond dates to cut us to same pattern meter just in different equation. He used the first equation of mentioned S e t great. And given that the final lost Ezio Andi as mentioned before the velocity, initial velocity and acceleration I love the directions to attach Really zero rebuilding minus 80. You was people to 80 and that is equal to new only a e o. Every day that party and Pardini sort of reverse engineered it. You don't have to have to calculate the basically the the Lost Stevenage Dorn's to its starting born. Because if we see that, we could deteriorate. Though it's basically the electric field is opposing a J. So is the electron actress initial stages in this die action? Andi, it's getting off force in this diatribe somewhere. The oddity come to hold. Great. This is what he found out that that that this distance is 3.67 to 10 for minus for me does until they 1.4 500 from minus 10 seconds. But now again, the forces still in this die action rates that will start traveling in this direction and again for now, you equal to zero for the distance equals 3.60 70. Then up minus with me does the acceleration of still seeing great You're and so I shining velocity will be five and do them by 60 meters for a second.

University of Toronto

#### Topics

Electric Charge and Electric Field

##### Marshall S.

University of Washington

##### Aspen F.

University of Sheffield

##### Jared E.

University of Winnipeg