Question

An electron in an excited state in a hydrogen atom can return to the ground state in two different ways: (a) via a direct transition in which a photon of wavelength $\lambda_1$ is emitted and (b) via an intermediate excited state reached by the emission of a photon of wavelength $\lambda_2$. This intermediate excited state then decays to the ground state by emitting another photon of wavelength $\lambda_3$. Derive an equation that relates $\lambda_1$ to $\lambda_2$ and $\lambda_3$. 

   An electron in an excited state in a hydrogen atom can return to the ground state in two different ways: (a) via a direct transition in which a photon of wavelength $\lambda_1$ is emitted and (b) via an intermediate excited state reached by the emission of a photon of wavelength $\lambda_2$. This intermediate excited state then decays to the ground state by emitting another photon of wavelength $\lambda_3$. Derive an equation that relates $\lambda_1$ to $\lambda_2$ and $\lambda_3$.
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Chemistry
Chemistry
Raymond Chang, Jason… 14th Edition
Chapter 7, Problem 117 ↓
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An electron in an excited state in a hydrogen atom can return to the ground state in two different ways: (a) via a direct transition in which a photon of wavelength $\lambda_1$ is emitted and (b) via an intermediate excited state reached by the emission of a photon of wavelength $\lambda_2$. This intermediate excited state then decays to the ground state by emitting another photon of wavelength $\lambda_3$. Derive an equation that relates $\lambda_1$ to $\lambda_2$ and $\lambda_3$.
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An electron in an excited state in a hydrogen atom can return to the ground state in two different ways: (a) via a direct transition in which a photon of wavelength $\lambda_{1}$ is emitted and (b) via an intermediate excited state reached by the emission of a photon of wavelength $\lambda_{2}$. This intermediate excited state then decays to the ground state by emitting another photon of wavelength $\lambda_{3}$. Derive an equation that relates $\lambda_{1}$ to $\lambda_{2}$ and $\lambda_{2}$.

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An electron in an excited state in a hydrogen atom can return to the ground state in two different ways: (a) via a direct transition in which a photon of wavelength $\lambda_{1}$ is emitted and (b) via an intermediate excited state reached by the emission of a photon of wavelength $\lambda_{2}$. This intermediate excited state then decays to the ground state by emitting another photon of wavelength $\lambda_{3}$. Derive an equation that relates $\lambda_{1}$ to $\lambda_{2}$ and $\lambda_{3}$
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Transcript

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00:01 Question 117.
00:02 An electron in an ascetic state in a hydrogen atom can return to the ground state in two different ways.
00:12 A, via direct transition in which photon of way length lambda 1 is emitted an n -level here.
00:25 Amidst this should be go from this level to this level.
00:29 So this will be electron here and lambda 1.
00:36 B via intermediate estitis test, reached by the emission of a photon wavelength lambda 2.
00:45 This intermediate is static state then decay to the ground set by emitting another photon of wavelength, lambda 3.
00:52 So we can imagine this statement like this after this electron don't go directly to the ground step, but they can go in this way.
01:01 It's stop around here.
01:02 Here, right? this is he lambda 2.
01:06 So from this intermediate state they continue to route this of this lambda 3.
01:13 But we know energy cannot lose.
01:16 Energy only transfer from this environment to another environment or from this state for another state...
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