00:01
So we have the first energy state.
00:04
We have the ground state energy, essentially, of two electron volts.
00:09
And we're going to set this equal to the equation for a particle in a box, which is planck's constant over eight times the mass of the particle, times the length squared of the box.
00:27
I left a space here because we also would like to know the energy in joules, because we're going to be working in units where the energy needs to be in joules.
00:39
And you would simply multiply two electron volts by 1 .6 times 10 to the minus 19.
00:52
And this would give you the energy in joules.
00:58
So that is 3 .6 o times 10 to the negative 19.
01:08
So we'll place that value right here.
01:17
And from this equation, which i'll just highlight, we can obtain the length l, and we're going to end up taking a square root because we have l squared.
01:29
So we'll place this equation down here and just work to get l.
01:52
So the first thing we want to do is multiply both sides by l squared, and then we're going to divide also by 3 .60 times 10 to the minus 19.
02:20
And of course right here, the length squared will cancel.
02:26
And now we have, and also this number will cancel on the left.
02:31
So we have l squared is equal to h squared over 8 times m times the, what's really the energy, 3 .60 times 10 to the minus 19.
02:45
And we just now have to substitute in the mass and planx constant.
02:55
And so we're dealing with an electron, so we'll place the mass right here.
03:16
And in the numerator, we have the square of planck's constant.
03:20
So we have 6 .626 times 10 to the minus 34 squared.
03:29
And when you calculate this, you get, well, actually, we need the square root of it.
03:39
So let me go ahead and rewrite this a certain way.
03:44
Just place a square root over everything, and the length will equal 4 .34 times 10 to the minus 10 meters...