00:01
To serve this exercise, we have to recall just a few expressions from the bor model of the hydrogen atom.
00:07
So, the expression from a board model that we have to remember is this expression for the orbital angular momentum.
00:18
And also, it will be useful for this exercise to remember the definition of kinetic energy as the linear momentum square divided by 2m.
00:30
Okay? now, in this problem, suppose that we have an electron, and this electron is bounded, is in the hydrogen atom, in a given quantum number that we don't know, but if we use bars model, we can measure the electron's linear momentum to be equal to 6 .65 times 10, to the minus 25 kilograms meter per second.
01:10
Now, knowing this, the exercise wants us to find what is going to be the electrons kinetic energy for the borrars model.
01:19
So this is the linear momentum for borr's model.
01:29
And knowing the definition that i gave you here, we can just substitute k, we can just substitute p and use m as the mass of the electron and then find what is the kinetic energy.
01:44
So, k is p squared, so 6 .65 times 10 to the minus 25 kilograms meter per second squared, divided by 2 times the electron's mass.
02:07
So the value that i'm going to use for the electrons mass is 9 .109 times 10 to the minus 31 kilograms.
02:20
Okay? so when we do this calculation, we're going to find that the kinetic energy is 2 .42 times 10 to the minus 19.
02:37
Now questions b and c wants us to find the angular, the orbital angular momentum of the electron, and its quantum number, okay, given the information that we found in question, that the exercise gave us and what we found on question a.
03:05
So i'm going to start by trying to find what is because i'm going to use this expression for the angular momentum.
03:13
And to use the expression, we have to know what is the value of n.
03:21
So to find n, i'm going to use that for bars model, the velocity of the electron for a given quantum number is one over the electric constant in vacuum times the electrons charge squared divided by two pi times blanks constant.
03:48
And v is going to be pretty straightforward for us to find, given that we know the kinetic energy already of the electron.
03:58
So, even better, we can use the definition for linear momentum.
04:13
So from the definition of linear momentum, we have the following...