Question
An electron is moving in the $+y$ -direction at $2.0 \times 10^{5} \mathrm{~m} / \mathrm{s}$ through a uniform magnetic field of $3.40 \mathrm{~T}$ in the $-x$ -direction. (a) What are the magnitude and direction of the force on the electron? (b) Find the electric field that would give zero net force on the electron.
Step 1
In this case, the electron is moving perpendicular to the magnetic field, so $\theta = 90^{\circ}$ and $sin(\theta) = 1$. Show more…
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