Question
An electron-positron pair is created in a particle detector. If the tracks of the particles indicate that each one has a kinetic energy of $0.22 \mathrm{MeV},$ what is the energy of the photon that created the two particles?
Step 1
This is given by the equation: \[E = 2mc^2 + k\] where \(m\) is the rest mass of the electron or positron, \(c\) is the speed of light, and \(k\) is the kinetic energy of each particle. Show more…
Show all steps
Your feedback will help us improve your experience
Anand Jangid and 71 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
How much total kinetic energy will an electron-positron pair have if produced by a 3.64 MeV photon? In MeV
An electron-positron pair is produced by a 2.50 MeV photon. What is the kinetic energy of the positron if the kinetic energy of the electron is 0.739 MeV? Use the following Joules-to-electron-Volts conversion: 1 eV = 1.602 × 10^-19 J. The rest mass of an electron is 9.11 × 10^-31 kg.
. A photon with an energy of $2.09 \mathrm{GeV}$ creates a protonantiproton pair in which the proton has a kinetic energy of $95.0 \mathrm{MeV}$. What is the kinetic energy of the antiproton?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD