Question
An electron with rest energy of $0.511 \mathrm{MeV}$ moves with speed $u=0.2 c$. Find its total energy, kinetic energy, and momentum.
Step 1
511 \mathrm{MeV}$, we can write this in terms of mass using the equation $E=mc^2$, where $E$ is energy, $m$ is mass, and $c$ is the speed of light. This gives us $m = E/c^2 = 0.511 \mathrm{MeV}/c^2$. Show more…
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An electron (0.511 MeV/c²) travels at a speed of 0.2c. Calculate (a) the total energy and (b) the momentum of the electron. (Ans: γ = 1.02, E = 0.522 MeV, p = 0.11); Ans. for 1b = 0.105 MeV/c; solve this equation using eq. E² = E₀² + (pc)².
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