Question
An element crystallizes in a face-centered cubic lattice. The edge of the unit cell is $0.408 \mathrm{nm}$, and the density of the crystal is $10.49 \mathrm{~g} / \mathrm{cm}^{3}$. Calculate the atomic weight of the element and identify the element.
Step 1
We know that 1 nm = 10ā»ā· cm. So, the edge length in cm is $0.408 \times 10^{-7}$ cm. Show more…
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