Question
An elevator cabin has a mass of $358.1 \mathrm{~kg}$, and the combined mass of the people inside the cabin is $169.2 \mathrm{~kg}$. The cabin is pulled upward by a cable, with a constant acceleration of $4.11 \mathrm{~m} / \mathrm{s}^{2} .$ What is the tension in the cable?
Step 1
This can be done by adding the mass of the elevator cabin and the mass of the people. \[m_{total} = m_{cabin} + m_{people} = 358.1 \, kg + 169.2 \, kg = 527.3 \, kg\] Show more…
Show all steps
Your feedback will help us improve your experience
Sachin Rao and 64 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
An elevator cabin has a mass of $363.7 \mathrm{~kg},$ and the combined mass of the people inside the cabin is $177.0 \mathrm{~kg} .$ The cabin is pulled upward by a cable, in which there is a tension force of $7638 \mathrm{~N}$. What is the acceleration of the elevator?
An elevator cabin has a mass of 380 kg, and the combined mass of the people inside the cabin is 180 kg. The cabin is pulled upward by a cable, in which there is a tension force of 7600 N. What is the acceleration of the elevator? a. 3.76 m/s2 c. 3.76 m/s2 b. 3.76 m/s2 d. 3.76 m/s2
An elevator with a mass of $2840 \mathrm{~kg}$ is given an upward acceleration of $1.22 \mathrm{~m} / \mathrm{s}^{2}$ by a cable. (a) Calculate the tension in the cable. (b) What is the tension when the elevator is slowing at the rate of $1.22 \mathrm{~m} / \mathrm{s}^{2}$ but is still moving upward?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD