An ellipse is orthogonal to the hyperbola $x^{2}-y^{2}=2 .$ The eccentricity of the ellipse is reciprocal of that of the hyperbola. Then
(a) equation of the ellipse is $x^{2}+2 y^{2}=8$
(b) focus of the ellipse is at $(-4 \sqrt{2}, 0)$
(c) directrix of the ellipse is $x+4 \sqrt{2}=0$
(d) directrix circle of the ellipse $x^{2}+y^{2}=12$