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An emf of 24.0 mV is induced in a 500-turn coil when the current is changing at a rate of 10.0 A/s. What is the magnetic flux through each turn of the coil at an instant when the current is 4.00 A?

0.0000192 T . m^{2}

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Cornell University

Rutgers, The State University of New Jersey

University of Washington

Hope College

were asked to find the magnetic flux through each turn of the coil. At an instance, when the current is four and peers so the magnetic flux can be found from the fact that the induct in CE l, which we can figure out from the potential Absalon divided by the change in current D I over DT well, the induct Ince's equal to the number of turns times the magnetic flux divided by the current I. But we want to know where the current is foreign peers. Therefore, the magnetic flux is equal to i times e m f So the current times e m f divided by the change of current with respect to time D I. D t multiplied by the number of Terrence plaguing these values of this expression, we find that this is equal to 1.92 times 10 to the minus five from the unit era test lis times meter squared. Oh, we can go ahead and box that it is a solution to our question.