Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

An engine of the orbital maneuvering system (OMS) on a space shuttle exerts a force of $(26,700 \mathrm{N}) \}$ for 3.90 $\mathrm{s}$ , exhausting a negligible mass of fuel relative to the $95,000-\mathrm{kg}$ mass of the shuttle. (a) What is the impulse of the force for this 3.90 s? (b) What isthe shuttle's change in momentum from this impulse? (c) What is the shutle's change in velocity from this impulse? (d) Why ean't we find the resulting change in the kinetic energy of the shuttle?

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

(a) $\vec{J}=104130 \mathrm{kg} \cdot \mathrm{m} / \mathrm{s} \hat{\mathrm{j}}$(b) $\Delta \overrightarrow{\mathrm{p}}=104130 \mathrm{kg} \cdot \mathrm{m} / \mathrm{s} \hat{\mathrm{j}}$(c) $\Delta \overrightarrow{\mathrm{v}}=1.096 \mathrm{m} / \mathrm{s} \hat{\mathrm{j}}$ (d) since the change in kinetic energy depends not only on the change in velocity but also on both the initial and final velocity. And since we can't get any of them, therefore we can't get the change in kinetic energy.

Physics 101 Mechanics

Chapter 8

Momentum, Impulse, and Collisions

Moment, Impulse, and Collisions

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Washington

Simon Fraser University

Lectures

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

03:30

In physics, impulse is the integral of a force, F, over the time interval, t, for which it acts. Given a force, F, applied for a time, t, the resulting change in momentum, p, is equal to the impulse, I. Impulse applied to a mass, m, is also equal to the change in the object's kinetic energy, T, as a result of the force acting on it.

05:34

An engine of the orbital m…

02:49

The space shuttle launches…

01:38

02:09

"The space shuttle la…

07:09

At time $t=0$ a $2150 \mat…

02:25

02:41

06:47

At time $t$ = 0 a 2150-kg …

05:04

At time $t=0,$ a $2150-\ma…

05:31

The space shuttle, togethe…

05:22

Unmanned Space Probe A $25…

03:48

A spacecraft engine create…

04:42

CALC At time $t=0,$ a 2150…

02:21

02:30

A model rocket is construc…

in this question, the orbital maneuvering system off that space shuttle exerts the force off 26,000 and 700 Newtons, pointing upwards that space shuttle has a mass off 95,000 kg on that force is exerted for 3.90 seconds in the first item. Off this question, we have to evaluate what is the impulse produced by that force during this 3.9 seconds? For that, we can use this expression, which tells us that the impulse is given by the force times the interval off time. And let me add that my reference frame for this question is this one. Everything that is pointing upwards is positive India's reference frame. So the impulse is given by the force off 26,000 and 700 Newtons times Delta T, which is 3.90 seconds. This results in an impulse off 104,000 and 130 but noticed that we had at most three significant figures for the time the reform. We must run the final results to treat significant figures. That means that the final result must be approximated to 104,000, and that's it. You can also write that as 1.4 times 10 to the fifth on the units are units off momentum kilograms, meters per second and this is the answer to the first item In the second item. We have to tell what is the variation in the momentum produced by that impulse? Well, the answer is that the variation in the momentum is equal to the impulse, as you can see from this relation so trivially. The answer to the second item is 1.4 times 10 to the fifth kilograms meters per second and that's it. Now we have to evaluate what is the change in the velocity? Well, the changing the velocity can easily be evaluated from the change in the momentum. So take a look at the following. The change in the momentum is equals to the final momentum, minus the initial momentum. The final momentum is given by the mass times. The final velocity on the initial momentum is given by the mass times the initial velocity notice that I'm not including the change in the mass that is produced by the exhaustion off you. Because the question says that the Mass. A few that was used to produce that force is negligible when compared to the mass of the shuttle. So you can consider the mass of the shuttle Toby approximately constant the reform, the changing, the momentum is given by the mass times, the final velocity minus the initial velocity or the mass times the change in the velocity. Therefore, the changing the velocity of the shuttle is given by the change in the momentum divided by its mass. Therefore, it is 1.4 time stand to the fifth, divided by 95,000 kg, and these results in approximately 1.9 m per second. Note that I approximated the final results to three significant figures because we only had three significant figures for the change in the momentum. Now the final item asks us, Why don't we evaluate the variation in the kinetic energy? Well, the reason is the following the variation in the kinetic energy is given by the final kinetic energy, minus the initial kinetic energy. The final kinetic energy is the mass of the Chateau times, its final velocity squared, divided by true. The initial kinetic energy is given by the mass of the shuttle times its initial velocity squared divided by True. Then we can factor out em over to so that the variation in the kinetic energy is given by the final velocity squared minus the initial velocity squared. The reform Delta K is equals to em over troop. We can write that product as VF plus zero times VF minus zero. The reform the variation in the momentum Delta K is given by em over two times VF plus zero times Delta v the reform. As you can see, it depends explicitly on the initial velocity. And we only know the variation in the velocity. So you're not able to evaluate the variation in the kinetic energy because we don't know what waas the initial velocity.

View More Answers From This Book

Find Another Textbook

06:36

30. block of mass m 5.8 kg is pulled up a 0 259 incline as in Figure P4.30 w…

02:24

34 Sound from foghorn in a lighthouse has a frequency of 100 Hz. Suppose tha…

01:09

Suppose an underground storage tank has been leaking for many years contamin…

02:33

d. (667 6o*0 5)5* Li Sih JL The spectrum of sodium (Na) has two closely-spac…

02:45

The figure shows four Gaussian surfaces surrounding distribution of charges_…

01:35

Two point charges of+2.0 UC and-6.0 HC are located on the x-axis atx =-1.0 c…

13:38

ballMass204kg has vclcity 0f mis; mass 29] kg nas velocity (a) Find …

01:59

A positron with a kinetic energy of 2MeV (mega electron-volt) collides with …

01:02

11. The position (aS & function of time) of a simple harmonic oscillator…

06:18

1S. Electric power is often produced by gas-powered generator Suppose output…