00:01
So in this question, we are given that we have an equiconque planes, an equiconque planes.
00:10
We are given the refractive index of the material, which is 1 .750.
00:18
We are given the power, which is minus 3 diatum.
00:23
And what we need to find is the radius of curvature.
00:28
We need to find the radius of curvature.
00:30
So this is the radius of curvature that we need to find out.
00:34
The radius of curvature are the same since this is an equiconcave lens.
00:39
So we need to find the radius of curvature.
00:41
So let us find the radius of curvature.
00:45
We know that power is equal to 1 upon f and 1 upon f is further equal to refractive index of the lens with respect to surrounding minus 1 and then 1 by r1 minus 1 by r2...