00:02
In this problem, we have a automobile traveling at a given velocity and is brought to rest in a given time.
00:11
We want to calculate the average impulsive force exerted by a man on the seatbelt and also the maximum force exerted on the seatbelt if the force time diagram is given a certain shape.
00:27
So firstly, let's look at our momentum impulse diagram.
00:32
So the person is moving with the initial momentum mv1 and when the car is brought to rest suddenly there is an impulse acting by the person onto the belt of fdt and the final momentum is zero when the system of the car and the person is brought to rest.
00:58
Now for part a, the force on the belt is opposite to the direction shown.
01:06
The initial velocity we have v1 is 45 miles an hour, which is 66 feet per second.
01:19
And the weight of the person, w, is 200 pounds.
01:27
So if we apply the principle of momentum and impulse, we get that mv1 minus the impulse fdt, is equal to m v2, the final momentum of the system.
01:49
Now ftt, the integral of fdt, is equal to the average force times the change in time, delta t, and delta t we are given.
02:18
So delta t we are given to be 0 .11 seconds.
02:23
So therefore if we go back to our equation, we get that 200 pounds, which is the weight of the man times his velocity 66 feet per second.
02:42
And we divide this by g to get his mass 32 .2 feet per square second minus the average force acting on the individual times the time of 0 .1 .1...