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An ethernet cable is 4.00 $\mathrm{m}$ long and has a mass of 0.200 $\mathrm{kg}$ . A transverse wave pulse is produced by plucking one end of the taut cable. The pulse makes four trips down and back

along the cable in 0.800 s. What is the tension in the cable?

80$N$

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McMaster University

so the down and back distance the round trip distance is eight meters, so two times 4.0 meters. So this would be a round trip essentially and so the speed then V would be equaling the total distance divided by tea. And so this would be equaling four times 8.0 meters and this would be divided 5.800 seconds. And this is giving us 40 0.0 meters per second, which we can also relate. This would be equaling to the square root the force over mu. And here we can say that then, um you would be the mass over length. So basically a linear density, this would be 0.200 kilograms divided by 4.0 meters. So the linear density is found to be point 0500 kilograms per meter. And we can then say that the force would be equaling the linear density multiplied by the velocity squared. So this would be 0.500 kilograms per meter multiplied by 40 0.0 meters per second quantity squared. And this is giving us a tea 0.0 Newton's. This would be our final answer. That is the end of the solution. Thank you for watching

Carnegie Mellon University