00:01
So for this problem, we're first going to find the resistance for each of these three rows of the table.
00:07
So for the first row, we have the resistance is equal to the voltage over the current of the first row.
00:16
We find that's equal to about 7 .25 oms.
00:22
Then for the second row, you just use the voltage of the second row over the current of the second row.
00:28
You find the resistance is equal to 14 .1 oms.
00:35
And then finally, same thing for row three, voltage of row three over the current of row three, and this is equal to 21 .2 oms.
00:47
And then we can use these values to find the resistivities of each row.
00:52
So we know that resistance is equal to the resistivity times the length over the area.
01:02
And so resistivity is equal to resistance times the area over the length.
01:10
So if we're looking for the resistivity of row one, we take the resistance of row one, which we found up here, times the area, which we're given in the problem, over the length in row one.
01:24
And we find this is equal to about 9 .8 times 10 to the negative 7.
01:30
0 .7 omm meters...