Question
An extreme value of $4 \sin ^{2} x+3 \cos ^{2} x-24 \sin \frac{x}{2}$$-24 \cos \frac{\mathrm{x}}{2}$, where $0 \leq \mathrm{x} \leq \frac{\pi}{2}$, is(A) $4+\sqrt{2}$(B) $4(1-6 \sqrt{2})$(C) $-21$(D) 4
Step 1
We can use the identity $\sin^2 x + \cos^2 x = 1$ to simplify the function as follows: \[f(x) = 4(1 - \cos^2 x) + 3 \cos^2 x - 24 \sin \frac{x}{2} -24 \cos \frac{x}{2}\] \[f(x) = 4 - 4\cos^2 x + 3 \cos^2 x - 24 \sin \frac{x}{2} -24 \cos \frac{x}{2}\] \[f(x) = 4 - Show more…
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