00:01
So in this problem, we have a ccd camera, which has a focal length of 105 millimeter, and f number equals 2 .8.
00:10
So we also know that the camera can focus an object from infinity down to 30 centimeter.
00:20
So what that means is the object distance can be p1 equals infinity down to p2 equals 300 millimeter.
00:28
So to solve the problem a, which is to find the diameter of the aperture of the lens, all we need to do is just use the definition of f number.
00:43
So let's do that.
00:47
So the definition of the f number is the ratio between the focal length of the lens and the diameter of the aperture, right? so from here the diameter of the aperture d is f over f number which is 105 millimeter over 2 .8.
01:17
This is going to give us 37 .5 millimeter.
01:24
So this is the diameter of the aperture.
01:30
All right.
01:31
So let's go to part b.
01:33
In part b, we want to find out the minimum distance between the lens and the cctv sensor.
01:40
Remember, that is also the image distance.
01:44
So that's what matters.
01:45
So to find the minimum distance, we have to assume that the object is at infinity.
01:52
All right.
01:53
So for part b, we are actually going to use object distance at infinity, which is p1 equals infinity...