00:01
All right, so here i've got drawn in ethanol -protected amino acid.
00:04
And the little b you see with the two dots i wrote is just a general base.
00:08
So in proposing a mechanism for the removal of this eflon group, it's said that we're going to use papyridine and water.
00:16
So this b with the two dots is going to act as both papyridine and water when it needs to be, just in both cases.
00:22
So an important thing to point out about this mechanism is that this hydrogen right here is incredibly acidic, considering where it is.
00:30
Is having a pca of around 20.
00:32
So it's definitely acidic enough to be abstracted or to be removed.
00:37
So i believe that the first step we should do is remove that hydrogen.
00:41
I'm going to have this base attacking the hydrogen there, and then this bond kind of shifting over one.
00:48
So what that's going to do is produce a pretty similar set of products, varying only really in one bond.
01:04
And that's the fact that that's a double bond now.
01:07
And oxygen, and then the rest of the molecule stays roughly the same, or i guess exactly the same.
01:25
So another important thing is that this carbon now probably has some sort of pseudo -positive charge on it, or maybe just a normal positive charge, because there were two protons on that carbon prior to the deprotonation, which means there's probably still two protons right there now, meaning that that definitely has a positive.
01:48
Charge.
01:49
So since we can kind of have that positive charge on that double bond, it's not super favorable.
01:56
What we can do is we can have this bond kind of just move onto the oxygen.
02:00
And there's two reasons we can do that.
02:02
The first is that the whole right side of this molecule with an amino acid with the additional carboxyl group is going to be a relatively good leaving group because you have a lot of carboxyl groups and you have a lot of hetero atoms that an electron charge can move on to.
02:16
The second part is that the bottom part is also going to be a good leaving group because it's a highly substituted kind of multi -ring structure.
02:24
Alright, so with that being said, we'll have the leaving group and we'll form kind of two big products out of that.
02:29
The first is going to be this ring structure, which forms there...