Question
An ice cube at $0^{\circ} \mathrm{C}$ measures $10.0 \mathrm{~cm}$ on a side. It sits on top of a copper block with a square cross section $10.0 \mathrm{~cm}$ on a side and a length of $20.0 \mathrm{~cm} .$ The block is partially immersed in a large pool of water at $90.0^{\circ} \mathrm{C} .$ How long does it take the ice cube to melt? Assume that only the part in contact with the copper liquefies; that is, the cube gets shorter as it melts. The density of ice is $0.917 \mathrm{~g} / \mathrm{cm}^{3}$.
Step 1
This can be done using the formula $Q = \rho V L_f$, where $\rho$ is the density of the ice, $V$ is the volume of the ice, and $L_f$ is the latent heat of fusion. Show more…
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An ice cube at $0.00^{\circ} \mathrm{C}$ measures $10.0 \mathrm{~cm}$ on a side. It sits on top of a copper block with a square cross section $10.0 \mathrm{~cm}$ on a side and a height of $20.0 \mathrm{~cm} .$ The bottom of the copper block is in thermal contact with a large pool of water at $90.0^{\circ} \mathrm{C}$. How long does it take the ice cube to melt? Assume that only the part in contact with the copper liquefies; that is, the cube gets shorter as it melts. The density of ice is $0.917 \mathrm{~g} / \mathrm{cm}^{3} .$
Approximately how long should it take 9.4 kg of ice at 0?C to melt when it is placed in a carefully sealed Styrofoam ice chest of dimensions 25 cm × 35 cm × 55 cm whose walls are 1.6 cm thick? Assume that the conductivity of Styrofoam is double that of air and that the outside temperature is 36 ?C.
A pond of water at $0{ }^{\circ} \mathrm{C}$ is covered with a layer of ice $4.00 \mathrm{~cm}$ thick. If the air temperature stays constant at $-10.0^{\circ} \mathrm{C}$, how long does it take the ice's thickness to increase to $8.00 \mathrm{~cm} ?$ (Hint: To solve this problem, use Equation $20.14$ in the form $$\frac{d Q}{d t}=k A \frac{\Delta T}{x}$$ and note that the incremental energy $d Q$ extracted from the water through the thickness $x$ of ice is the amount required to freeze a thickness $d x$ of ice. That is, $d Q=L \rho A d x$, where $\rho$ is the density of the ice, $A$ is the area, and $L$ is the latent heat of fusion.)
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