Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

An ice cube of mass 9.0 g is added to a cup of coffee. The coffee's initial temperature is 90.0 degree C and the cup contains 120.0 g of liquid. Assume the specific heat capacity of the coffee is the same as that of water. The heat of fusion of ice (the heat associated with ice melting) is 6.0 kJ/mol. Find the temperature of the coffee after the ice melts.

$78.1^{\circ} \mathrm{c}$

Chemistry 102

Chemistry 101

Chapter 9

Thermochemistry

Thermodynamics

Chemical reactions and Stoichiometry

University of Central Florida

Rice University

University of Maryland - University College

University of Kentucky

Lectures

00:42

In thermodynamics, the zer…

01:47

A spontaneous process is o…

09:11

An ice cube of mass 9.0 $\…

04:10

An ice cube with a mass of…

02:33

Given 400.0 g of hot tea a…

03:12

An ice-cube tray of neglig…

04:45

A 30.0-g ice cube at its m…

03:38

03:40

. An ice-cube tray contain…

03:54

How many grams of coffee m…

05:12

05:40

Your 300 mL cup of coffee …

01:26

An 8.5 g ice cube is place…

07:30

An 8.5-g ice cube is place…

03:16

A 20.0 -g sample of ice at…

07:35

A $20.0-\mathrm{g}$ sample…

05:01

What mass of ice can be me…

04:55

(II) A cube of ice is take…

02:54

How much heat (in kJ) is r…

06:28

An ice-cule tray of neglig…

05:17

How much heat (in $\mathrm…

02:41

So in this question we are told about an ice cube of mass 9 gram mass of ice. Yes, 9 grams was added to a cup of coffee and initial temperature of coffee, so temperature of coffee is 90 degrees celsius and the cop contains 123 gram of liquid. So mass of coffee is 120 grams, so, as in the specific capacity of copies that of water, so cato is 4.181 joe gram degree celsius. The heat of fusion of high it's teaffein, 6.0 kilo, joules mole, find the temperature of the coffee after the highest melt. So each lost by coffee is to gain by irons, so each lost by coffee is negative. Mass of coffee multiplied by specific its capacity of coffee, multiplied by delta t, which will be the final temperature of the mixture minus the initial temperature of cow is 90.0 degrees. Celsius is equal to heat gained by highand. That is the mass of his that's. 9.0 grams. Multiplied by specific heat capacity of his his multiplied by t, fine and minus initial temperature high genasium, that's be 0 degrees celsius, so the data he of fusion has beginning. We don't really have to trouble our set too much, and that is just when you have high solid water going to liquid water is to liquid, and that is for 1, more that we have 9.0 grams. So that is, if we convert is to mole. That is 0.5 moles and each of this reaction, the we need to multiply by 6.0. So that means that that means that q or melt into is 6.0 kilo, joule mole times 0.5 mole, and this would give us 3.0 kilo joules, okay. So knowing this, it's going to be very easy for us to calculate delta t, because we know that this as a whole should give us this value. Or we can say this as a whole- should give us this body. But it's just going to be the positive end. So what do we do? What you do e say that say so you can just go ahead and say this is the mass of is 120 minus 1 h, 20 times its capacity of copy 4.1 h 4 times. T f, minus 90.0 is equals to 9.0 gram multiplied by, but its capacity of his multiplied by t f, minus 0 degrees celsius is equal to 3.0 kilojoules, so we can take any of these 2 and quite them to 3.0 it. So it's better to take this. So if we take this, you say minne .3 times 4.1, it 4 times, t f. Minus 90.0 is equal to 3.0. We can convert these 2 joules because there's a joule in standard, pier 3 joules, therefore t f, minus 90.0. You be forsete 3.0 times time square 3, divided by 1 hue 28 times 4.184. Joules now give us hill give us 5.98 degrees celsius. Well then, we have to remember that it's going to carry a negative because of this negative sign. We should put the negative point. So going to the next page, t f, minus 19, o 92.0 is equals to minus 5.98 to 10 will be minus 5.98 plus 19, and that will give us 84.02 degrees celsius. So that will be the fine temperature, so we have took to find a temperature after the highest males. But at this point we have 9.0 gram of water at 0 degrees celsius and 120 grams of coffee after 84 degrees celsius. Therefore, the final equilibrium will be. It will be, the temperature is equilibrium. Temperature have olibrium, will be the mass of his multiplied by the temperature of highs, plus mass of coffee multiplied by temperature of coffee divided by massifs plus mass mass of coffee. So this would give us 9.0 times 0 cross 120 times 84 over 9 plus 1 in, and that will give us onethat will give us 78.1 degradate.

View More Answers From This Book

Find Another Textbook

In thermodynamics, the zeroth law of thermodynamics states that if two syste…

A spontaneous process is one in which the total entropy of the universe incr…

An ice cube of mass 9.0 $\mathrm{g}$ is added to a cup of coffee. The coffee…

An ice cube with a mass of 20 $\mathrm{g}$ at $-20^{\circ} \mathrm{C}$ (typi…

Given 400.0 g of hot tea at $80.0^{\circ} \mathrm{C}$ , what mass of ice at …

An ice-cube tray of negligible mass contains 0.350 $\mathrm{kg}$ of water at…

A 30.0-g ice cube at its melting point is dropped into an aluminum calorimet…

An ice-cube tray of negligible mass contains 0.290 kg of water at 18.0$^\cir…

. An ice-cube tray contains 0.350 $\mathrm{kg}$ of water at $18.0^{\circ} \m…

How many grams of coffee must evaporate from 350 g of coffee in a 100-g glas…

How many grams of coffee must evaporate from 350 g of coffee in a 100 -g gla…

Your 300 mL cup of coffee is too hot to drink when served at 90 $^{\circ} \m…

An 8.5 g ice cube is placed into 255 g of water. Calculate the temperature c…

An 8.5-g ice cube is placed into 255 g of water. Calculate the temperature c…

A 20.0 -g sample of ice at $-10.0^{\circ} \mathrm{C}$ is mixed with 100.0 g …

A $20.0-\mathrm{g}$ sample of ice at $-10.0^{\circ} \mathrm{C}$ is mixed wit…

What mass of ice can be melted with the same quantity of heat as required to…

(II) A cube of ice is taken from the freezer at $-8.5^{\circ} \mathrm{C}$ an…

How much heat (in kJ) is required to warm 10.0 g of ice, initially at -10.0 …

An ice-cule tray of negligible mass contains 0.350 $\mathrm{kg}$ of water at…

How much heat (in $\mathrm{kJ} )$ is required to warm 10.0 $\mathrm{g}$ of i…

How many grams of coffee must evaporate from 350 g of coffee in a $100-\math…

02:57

Write a short paragraph describing chemical bonding according to the Lewis m…

01:31

Some laboratory procedures involving oxygen-sensitive reactantsor produc…

03:20

A saturated solution forms when 0.0537 L of argon, at a pressureof 1.0 a…

02:27

When HNO2 dissolves in water, it partially dissociates accordingto the e…

02:17

A 0.5224-g sample of an unknown monoprotic acid was titratedwith 0.0998 …

04:37

How many hybrid orbitals do we use to describe each molecule?a. N2O5…

Use the given molar solubilities in pure water to calculate Ksp foreach …

03:14

Use the mass spectrum of europium shown here to determine the atomic mass of…

03:07

We mix 50.0 mL of ethanol (density = 0.789 g>mL) initially at 7.0 C with…

00:50

Using scanning tunneling microscopy, scientists at IBM wrote the initials of…