00:01
So here we have 18 ice cubes and there are 30 grams each.
00:06
So we can just times these together to get the amount, the total amount of water that we have in the tray, which is 540 grams of h2o.
00:21
And so first we need to figure out how much heat is required to, or how much energy is required to freeze this water.
00:33
And then we can use that energy and use the heat of vaporization for the cf to cl2 to then find how many grams we need of that to vaporize to do this process.
00:55
So first we have water.
00:58
We have liquid water.
00:59
So let's put water.
01:01
And we need to get that to zero degrees celsius first.
01:05
So first, it's at 22 degrees celsius to start.
01:12
So we need to get that, so we need to reduce that to zero degrees now.
01:18
So we can use q equals mc delta t.
01:24
Let me make that a little bit neater.
01:27
M .c.
01:27
Delta t.
01:29
And so we know mass, the mass, we already found that out, 540 grams.
01:36
And we know the specific heat of water.
01:39
Which is given in the problem, liquid water, and then conveniently you'll see that the grams cancel out and the temperature cancels out and it's 22 degrees because 22 minus 0 is 22.
01:56
And that gives us after rounding for sig -figs 49 ,700 joules.
02:06
So now since we have all of our water, liquid water at zero degrees, now we need to have the phase change.
02:14
So we need to go to from water...