00:01
In this problem, we'll see how a skater manages to spin their self up into a faster spin by tucking their arms closer to their body.
00:12
The concept we use here is conservation of angular momentum, which is something that you can apply if there's no net external torque, no external torque acting on a body, or if that external torque is negligent.
00:31
Which we assume is true because this person is on ice and there's nothing creating a force far away from the axis of the spin.
00:47
Reminder, angular momentum is l and it is calculated as the product of the moment of inertia times the angular velocity, the rotational analogs of mass times linear velocity.
01:06
But here we know the initial omega angular velocity of the spin before the tuck is four rads per second.
01:18
And what we know is that the moment of inertia drops by 7 .5%.
01:27
So that would bring it down to a factor of, 92 .5 % of the initial moment of inertia.
01:42
Okay, there we go.
01:45
Okay, but we'll want to set the initial and final angular momenta equal to each other, and it is the omega -2 that we are trying to determine.
02:07
So we can solve for that.
02:13
Thankfully, we don't have to know.
02:16
The absolute value of the moment of inertia, just how much it dropped by, and the initial angular velocity, we do know absolutely.
02:39
So we can work out that, yes, their final angular velocity is a little bit bigger, goes up to 4 .3 rads per second.
02:54
And it's an interesting question.
02:56
This is not an elastic type of situation where mechanical energy is conserved necessarily...