Question
An ideal gas is initially at temperature $T$ and volume $V$. Its volume increases by $\Delta V$ due to an increase in temperature of $\Delta T$, pressure remaining constant. The quantity $\delta=\frac{\Delta V}{V \Delta T}$ varies with temperature as
Step 1
Step 1: We start with the ideal gas equation, which is given by $PV = nRT$, where $P$ is the pressure, $V$ is the volume, $T$ is the temperature, $n$ is the number of moles, and $R$ is the gas constant. Show more…
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An ideal gas undergoes a constant volume (isochoric) process in a closed system. The heat transfer and work are, respectively $(a) 0,-c_{v} \Delta T$ (b) $c_{v} \Delta T, 0$ $(c) c_{p} \Delta T, R \Delta T$ $(d) R \ln \left(T_{2} / T_{1}\right), R \ln \left(T_{2} / T_{1}\right)$
An ideal gas undergoes a constant temperature (isothermal) process in a closed system. The heat transfer and work are, respectively $(a) 0,-c_{v} \Delta T$ (b) $c_{v} \Delta T, 0$ (c) $c_{p} \Delta T, R \Delta T$ (d) $R \ln \left(T_{2} / T_{1}\right), R \ln \left(T_{2} / T_{1}\right)$
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