Question
An ideal gas is taken $\mathrm{V}$ path ACBA as Shown in figure, The net work done in the whole cycle is(A) $-3 \mathrm{P}_{1} \mathrm{~V}_{1}$(B) Zero(C) $5 \mathrm{P}_{1} \mathrm{~V}_{1}$(D) $3 \mathrm{P}_{1} \mathrm{~V}_{1}$
Step 1
Step 1: The net work done in a cyclic process is equal to the area enclosed by the cycle in the P-V diagram. Show more…
Show all steps
Your feedback will help us improve your experience
Sachin Rao and 69 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
An ideal gas is taken around the cycle $A B C A$ as shown in $P-V$ diagram. The net work done during the cycle is equal to : (a) $12 P_{1} V_{1}$ (b) $6 P_{1} V_{1}$ (c) $5 P_{1} V_{1}$ (d) $P_{1} V_{1}$
An ideal gas is taken around ABCA as shown in the above $P-V$ diagram. The work done during a cycle is: (a) $2 \overline{P V}$ (b) $3 \mathrm{PV}$ (c) $4 P V$ (d) $2.5 \mathrm{PV}$
THERMODYNAMICS
Thermodynamics
An ideal monoatomic gas is taken around the cycle $A B C D$ as shown in $p$ versus $V$ diagram. Work done during the cycle is (a) $p V$ (b) $0.5 p \mathrm{~V}$ (c) $2 p \mathrm{p}$ (d) $3 p V$
Round 1
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD