Question
An ideal heat engine working between temperature $\mathrm{T}_{1}$ and $\mathrm{T}_{2}$ has an efficiency $\eta$. The new efficiency if both the source and sink temperature are doubled, will be(A) $\eta$(B) $2 \eta$(C) $3 \eta$(D) $(\eta / 2)$
Step 1
Step 1: The efficiency of an ideal heat engine is given by the formula: \[\eta = 1 - \frac{T_2}{T_1}\] Show more…
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