00:01
We will be using bond enthalpies to compare two reactions.
00:07
Each of these reactions is the reaction of ethane to, or excuse me, of methane to ethane.
00:18
We are given two reactions.
00:19
The first reaction is to ch4, produces c2h6 plus h2, and all of these are gases.
00:41
My earbud fell out.
00:45
In reality, this reaction is carried out in the presence of oxygen.
00:56
Again, the first reaction and the reaction i'm writing right now are both provided in the problem.
01:20
And we're told to use bond enthopies from table 8 -4 in the textbook to estimate the change of enthalpy for these two reactions.
01:31
We're also going to compare why the code conversion of methane to ethane is more favorable when oxygen is used.
01:41
So in order to do this, i'm going to write down how many of each type of bonds there are.
01:47
I have four ch bonds here, and i have two methane for a total of eight c .h bonds.
02:00
Here, i have one carbon -carbon bond and six c -h bonds, and i have.
02:10
I have one hydrogen -hydrogen bond.
02:17
We have the same thing right here, same thing, so i have eight c -h bonds.
02:22
The same thing right here, so i have one, c, c, and six, c -h.
02:28
Here i have half an o2, and for the h -2o, i have two o -h bonds.
02:39
And looking at these, i have c -h bonds here and here.
02:50
I can see that i will have these cross out and i'll have two of these left, which means i'll have two ch bonds and i look up ch and i see that it is 413 kilojoules per mole...