00:02
So this question is asked you to determine the equilibrium constant.
00:11
So for this reaction, if the 900k, the initial concentration, well, the initial moles of so2 is 0 .0216 more, and oxygen is 0 .148, and oxygen is 0 .148.
00:54
More, the volume of vessel right here is 1 .0 later.
01:03
So basically that will be the concentration, so initial concentration.
01:20
And it said at equilibrium state, at equilibrium state, the concentration of an so3 is 0 .0175m.
01:37
So what is the kc? so to determine the kc we need to determine the concentrations of all species at equilibrium.
01:50
So now good news is that we know the concentration of this and therefore we know how many more of so3 we have.
02:05
So basically because total volume is 1 .0 later so you have 0 .0175 more of so3 because the initial concentration or the initial quantity of so3 is zero so therefore we can think this is also the change well this is the converted so3 so therefore, the concentration, well, the moles of so oxygen, but the equilibrium will be the initial moles minus that is converted because every one more of so3, you're going to only need half more of s oxygen.
03:06
So that will give you mores of oxygen at equilibrium state, which will be 0 .0605...