We know that the area $A_3$ is given by the formula $\frac{\pi}{4}D^2$, where $D$ is the diameter of the section. Given that $D_3 = 0.13$ m, we can substitute this into the formula to get:
\[A_3 = \frac{\pi}{4} \times (0.13)^2 = 0.0132 \, \text{m}^2\]
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