Question
An indicator has a $\mathrm{p} K_{\mathrm{a}}$ of $5.7 .$ It is colorless in acid solution and deep green in alkaline solution.(a) What is its $K_{\mathrm{a}}$ ?(b) What is its pH range?(c) What would its color be at pH $5.7 ?$
Step 1
Therefore, we can calculate $K_{\mathrm{a}}$ using the formula $K_{\mathrm{a}} = 10^{-\mathrm{p} K_{\mathrm{a}}}$. Show more…
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