00:01
So a person, a near -sided person has his near point at 13 cm and far point at 50 centimeter.
00:10
So let's find the power of the lens needed for this person.
00:16
So to find the power, since the person is near -sided, a virtual and upright image should form at his far point when he uses corrective lens to see a distant object.
00:28
Okay, so that means p, when p equals infinity, q has to be at negative 50 centimeter.
00:43
So from the lens equation, which is 1 over f equals 1 over p plus 1 over q, 1 over p is going to be 1 over infinity, which is 0, and 1 over q is going to be negative 1 over 50.
01:02
So from here you can see that actually f is going to be negative 50 centimeter as well.
01:12
So i'm just going to write this down in meters, 0 .5 meter.
01:18
Okay...