Question
An inductor has a $54.0-\Omega$ reactance when connected to a 60.0 -Hz source. The inductor is removed and then connected to a 50.0 - Hz source that produces a 100. - V rms voltage. What is the maximum current in the inductor?
Step 1
We can rearrange this formula to solve for $L$: \[L = \frac{X_L}{2\pi f}\] Substituting the given values for $X_L$ and $f$ (54.0 Ω and 60.0 Hz respectively), we get: \[L = \frac{54.0}{2\pi \times 60.0} = 0.14331 \, \text{H}\] Show more…
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An inductor has a $54.0-\Omega$ reactance when connected to a $60.0-\mathrm{Hz}$ source. The inductor is removed and then connected to a $50.0-\mathrm{Hz}$ source that produces a $100-\mathrm{V}$ rms voltage. What is the maximum current in the inductor?
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