Question
An inductor $(L=400 . \mathrm{mH}),$ a capacitor $(C=4.43 \mu \mathrm{F})$ and a resistor $(R=500 . \Omega)$ are connected in series. A 50.0 - Hz AC generator connected in series to these elements produces a maximum current of 250 mA in the circuit. (a) Calculate the required maximum voltage $\Delta V_{\max }$ (b) Determine the phase angle by which the current leads or lags the appliedvoltage.
Step 1
Substituting the given values, we get: \[X_L = 2\pi \times 50.0 \, Hz \times 400 \times 10^{-3} \, H = 126 \, \Omega\] \[X_C = \frac{1}{2\pi \times 50.0 \, Hz \times 4.43 \times 10^{-6} \, F} = 719 \, \Omega\] Show more…
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An inductor $(L=400 \mathrm{mH})$, a capacitor $(C=4.43 \mu \mathrm{F})$, and a resistor $(R=500 \Omega)$ are connected in series. $\underline{A}$ $50.0-\mathrm{Hz}$ AC generator connected in series to these elements produces a maximum current of $250 \mathrm{~mA}$ in the circuit. (a) Calculate the required maximum voltage $\Delta V_{\max }$ (b) Determine the phase angle by which the current leads or lags the applied voltage.
An inductor $(L=400 \mathrm{mH})$, a capacitor $(C=4.43 \mu \mathrm{F})$, and a resistor $(R=500 \Omega)$ are connected in series. A $50.0-\mathrm{Hz}$ ac generator produces a peak current of $250 \mathrm{~mA}$ in the circuit. (a) Calculate the required peak voltage $\Delta V_{\max }$. (b) Determine the phase angle by which the current leads or lags the applied voltage.
An inductor $(L=400 \mathrm{mH}),$ a capacitor $(C=4.43 \mu \mathrm{F})$ and a resistor $(R=500 \Omega)$ are connected in series. A $50.0-\mathrm{Hz}$ AC source produces a peak current of 250 $\mathrm{mA}$ in the circuit. (a) Calculate the required peak voltage $\Delta V_{\text { max }}$ (b) Determine the phase angle by which the current leads or lags the applied voltage.
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