00:01
Suppose we know some things about the power in a collimated beam of light, say, from a laser.
00:08
So we know the power in the beam, and we know the diameter of the beam d.
00:15
And we also know the wavelength, let's say, just for the sake of argument, that the wavelength is known as well.
00:25
And we would like to come up with expressions for the instantaneous electric and magnetic field.
00:32
In the electromagnetic wave that is carrying that energy.
00:39
How would we do that? first of all, we need to know the direction of travel of the beam.
00:46
Okay, so we are going to write down the electric field and the magnetic field, but if we know the direction of travel of the beam, then we basically know the direction of the s factor, the pointing factor.
01:02
So let's pretend that we know that that is in the z hat direction.
01:10
And so s is also in the z direction.
01:17
That is the direction of energy flow, which is perpendicular to both e and b.
01:33
And it is expressions for those that we are trying to find.
01:38
So one way to satisfy this would be if e is, polarized in the x direction.
01:49
Remember that polarization typically means the direction that the electric field is pointing.
01:57
So if we were to draw the electric field inside of this wave, it would go along the x direction and then switch to the minus x direction.
02:14
And then in order to be traveling in the positive z direction, the magnetic field would then be pointing in the y direction, which according to my drawing first comes out of the plane, and then it goes into the plane.
02:48
So yes, the cross -product between those two points to the right.
02:58
So x cross -y gives us c.
03:02
Now, if we know the power in the beam and the diameter of the beam, we configure the time -average pointing vector.
03:13
Average s, and it's both time - and space -average, is equal to the power in the laser, for example, divided by the area of the beam.
03:26
And here we are assuming a circular beam cross -section.
03:30
That's a little bit of a simplification, but we'll go ahead and do that.
03:37
And here we know the diameter, so we can figure out the area from pi r squared.
03:51
And that time averaged s is equal to, in terms of watts per meter, quite big.
04:11
Let me check my number.
04:27
Try it again until i get the same answer twice.
04:35
And let me see if i have the diameter.
04:40
It's 100 micrometers, yes.
04:42
That is an issue.
04:45
A hundred micrometers in diameter.
04:56
So the beam radius will be 50 times 10 to the minus 6 meters.
05:02
There we go.
05:11
Always good to verify that.
05:12
And so this is about 7 .64 times 10 to the 11th watts per meter squared.
05:23
And from that, we can use this to find the amplitude of the electric field.
05:36
That is the maximum amplitude, not the rms amplitude.
05:41
And then we can simply find the amplitude of the magnetic field by taking that quantity and dividing by the speed of light.
05:55
So yeah, solving we have e knot is the square root of 2 times s average over c times the permittivity of free space...