An input voltage of $2 \mathrm{~V} \mathrm{rms}$ (measured from base to ground) is applied to the circuit of Fig. 21 . Assuming that the emitter voltage follows the base voltage exactly and that $V_{b e}(\mathrm{rms})=0.1 \mathrm{~V}$, calculate the circuit voltage amplification $\left(A_{v}=V_{o} / V_{i}\right)$ and emitter current for $R_{E}=1 \mathrm{k} \Omega$.