00:01
An insulated mixing chamber receives r134a at a given state with a low line velocity.
00:08
And another line brings in r134a as well as a saturated liquid at a different state.
00:16
We are given a single exit flow state and velocity, and we want to find the mass flow rate for the second line.
00:25
So if we take our control volume for mixing chamber, we have a steady state process with two inlets and one exit flow.
00:33
There is no heat transfer, nor is there any work due to shaft or boundary work.
00:41
So we'll first write the continuity equation for this process.
00:52
The continuity equation is simply the mass flow rates of the two inlets, m .1, plus m .2, the two inlet lines must equal to the mass flow rate at the exit m .3.
01:07
And so we can then write the energy equation, which also simplifies.
01:17
As m .1, h1, which is the enthalpy plus m.
01:25
Dot 2, h2, is equal to the energy at the exit duct, which is m .03 into h3 plus the kinetic energy term, a half v3 squared.
01:44
So we can rewrite this equation.
01:47
Remember we want to find m .2 here.
01:50
The flow rate, the mass flow rate of the second line.
01:53
So rearranging this equation and making it easier to solve for m2 or m .2, we can group this as m .2 into h2 minus h3 and this is using our continuity equation from above minus a half v3 squared is equal to m .1.
02:17
So essentially we're replacing m .3 with m .1 plus m...