Question
An integrating factor of the equation $\frac{d y}{d x}-\frac{x-2}{x(x-1)} y=\frac{x^{2}(2 x-1)}{x-1}$, is(a) $\frac{x+1}{x^{2}}$(b) $\frac{x-1}{x^{2}}$(c) $\frac{x^{2}}{x+1}$(d) $\frac{x^{2}}{x-1}$
Step 1
Comparing this with the given equation, we get $P(x) = -\frac{x-2}{x(x-1)}$. Show more…
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