00:01
So we have a matched pair setting, and i'm going to let my difference be the after minus the before, the number of contaminants that they found.
00:10
And we will be assuming that the mean difference is equal to zero, and alternately that that mean difference will be negative, so that this number will be a lesser number than before, and we're using a 5 % significance level.
00:24
And so when i did my calculation for my values, i'm getting the sample size again for those differences.
00:33
We have eight of them, and we have the mean of those differences as a negative 3 .1125 with a sample standard deviation of 2 .911, and i would have ground to three for another decimal place.
00:51
And so we are using a t value here, and we would be putting all of our 5 % in the, the lower tail and we would have our critical value would have eight degrees of freedom excuse me seven degrees of freedom and we want to have our critical value here with five percent in that lower tail will be negative 1 .895 so we're down here if our test statistic comes out below this value will be rejecting our no and if it is higher then we would fail to reject the no and say that in the new soap does not make a significant difference.
01:30
So let's find our test statistic.
01:32
So we have that negative 3 .1125 minus the mean we're assuming and then our sample standard deviation divided by the square root of 8.
01:42
And that test statistic is quite negative, 3 .02 and it would round a 4...