00:01
Here on this problem, we've been given the following cumulative distribution function, and we'd like to find a few different probabilities from this.
00:08
Now, it is important to remember that for our probability, for our distribution function, that f of t is equal to the probability, that t is less than equal to t.
00:23
And so we want to use this here to find several different probabilities.
00:29
Now, from this first, we want to find the probability of t being equal to five.
00:42
Now you'll notice that at 5 when it's equal to it, that's 3 .4s.
00:47
But as we approach 5, it's just 1⁄2.
00:52
And so this means the probability that it is exactly 5 would be 3 4s minus 1⁄2, which is 1 4th.
01:01
And so the probability that 5 is 1 4th.
01:06
On b, we want to find the probability that t is greater than 3.
01:14
And the probability that t is greater than 3 is equal to 1 minus the probability that t is less than or equal to 3.
01:23
Which is 1 minus f of 3 and from the chart there we know that f of 3 is 1 1 1 1 .5 and so this is 1 minus 1 half which is 1 1 1 1.
01:43
C you want the probability that t is between 1 .4 and 6 and so this is equal to the probability that t is less than equal to 6 minus the probability that t is less than equal to 1 .4 and so this is f of 6 minus f of 1 .4 f of 6 is the 0 .6 this is the 2...