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An ion having charge $+6 e$ is traveling horizontally to the left at 8.50 $\mathrm{km} / \mathrm{s}$ when it enters a magnetic field that is perpendicular to its velocity and deflects it downward with an initial magnetic force of $6.94 \times 10^{-15} \mathrm{N} .$ What are the direction and magnitude of this field? Illustrate your method of solving this problem with a diagram.

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Physics 101 Mechanics

Physics 102 Electricity and Magnetism

Chapter 20

Magnetic Field and Magnetic Force

Motion Along a Straight Line

Motion in 2d or 3d

Electric Charge and Electric Field

Gauss's Law

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Magnetic Field and Magnetic Forces

Sources of Magnetic field

Electromagnetic Induction

Inductance

Cornell University

Simon Fraser University

Hope College

University of Winnipeg

Lectures

18:38

In physics, electric flux is a measure of the quantity of electric charge passing through a surface. It is used in the study of electromagnetic radiation. The SI unit of electric flux is the weber (symbol: Wb). The electric flux through a surface is calculated by dividing the electric charge passing through the surface by the area of the surface, and multiplying by the permittivity of free space (the permittivity of vacuum is used in the case of a vacuum). The electric flux through a closed surface is zero, by Gauss's law.

04:28

A magnetic field is a mathematical description of the magnetic influence of electric currents and magnetic materials. The magnetic field at any given point is specified by both a direction and a magnitude (or strength); as such it is a vector field. The term is used for two distinct but closely related fields denoted by the symbols B and H. The term "magnetic field" is often used to refer to the B field. In a vacuum, B and H are the same, whereas in a material medium, B is a component of H. In the latter case, H is the "magnetic field strength", and B is the "magnetic flux".

01:02

An ion having charge +6e i…

02:02

The magnetic field of Eart…

03:16

An ion having charge ~6e i…

01:37

An ion having charge +…

01:03

A particle of charge $q=-8…

02:51

The magnetic field of the …

14:36

A group of particles is tr…

03:39

In a 1.25-T magnetic field…

01:07

$\bullet$ In a 1.25 T magn…

03:47

(a) Find the direction and…

so we can draw a quick diagram of the vectors. We have the positive charge, and then acting to the left is the velocity. So it's moving to the left. Um, the magnetic field is up, is pointed upwards and then out of the page. Well, we can actually say that out of the page is the force. So we know that the charges equaling plus six times e and we know that the velocity of the charge is 8.50 kilometers per second on. We know that the magnitude of the force is going to be equal to 6.9 for times 10 to the negative 15th Nunes s. So at this point, we confined that the force we know rather be note the force is going to be equal to the absolute value of the charge times the velocity of the charge times the magnetic field time. Sign off. Five. We know it's certify whether sign, if I equals tau equals one. So we can say that the magnetic field, the magnitude of the magnetic field is simply the magnitude of the force divided by the magnitude of the charge times. The magnitude of the velocity. So to solve for the magnetic field, we can simply say that it'll be F S O B 6.9 for times 10 to the negative 15th Newtons time out of a six times 1.6 times turned to the native 19th cool arms times 85 100 meters per second and this is equaling 0.850 t. So 0.850 Tesla's is the magnitude of the magnetic field. And again, this is a quick the diagram of the vectors that are present here. That is the end of the solution. Thank you for watching.

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