We are given that the potential difference is $60.0 \mathrm{V}$ and the change in electrical potential energy is $1.92 \times 10^{-17}$ J. Plugging these values into the equation, we have:
\[ 60.0 = \frac{1.92 \times 10^{-17}}{q} \]
To solve for q, we can
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