Question
An iron ball has a diameter of $6 \mathrm{~cm}$ and is $0.010 \mathrm{~mm}$ too large to pass through a hole in a brass plate when the ball and plate are at a temperature of $30^{\circ} \mathrm{C}$. At what temperature (the same for ball and plate) will the ball just pass through the hole? $\alpha=1.2 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1}$ and $1.9 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1}$ for iron and brass, respectively.
Step 1
Since the iron ball is 0.010 mm too large to pass through the hole, the diameter of the hole must be 6 cm - 0.010 mm = 60 mm - 0.010 mm = 59.990 mm. Show more…
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