Question
An iron rod of length $L$ and magnetic moment $\mathrm{M}$ is bent in the form of a semicircle. Now its magnetic moment will be(a) $\mathrm{M}$(b) $(2 \mathrm{M} / \pi)$(c) $(\mathrm{M} / \pi)$(d) $\mathrm{M} \pi$
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Magnetic moment per unit length = M / L Show more…
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