00:01
Problem 107 asks you to find the percent mass to volume of each solution if that solution is isotonic.
00:08
And the problem tells you that a 0 .90 % solution of sodium chloride is isotonic.
00:14
So the first thing that we can do to help ourselves out here is figure out the molarity of a 0 .90 % sodium chloride solution.
00:23
So what we know about mass to volume percentages is that that translates to 0 .90 grams of sodium chloride per 100 mils of water.
00:41
You can then convert that to grams per liter and then multiply by the molecular weight or divide by the molecular weight, of sodium chloride to get moles per liter or molarity.
01:04
So that gives us 0 .154 molar.
01:08
So 0 .154 molar then is the molarity of an isotonic solution.
01:14
Now remember that that only takes into account sodium chloride as a whole, but what you have to remember is that because sodium chloride is an electrolyte or a salt, it breaks into 0 .154 moles of sodium and 0 .154 moles of chloride in solution.
01:38
And so each electrolyte like sodium chloride, like calcium chloride, which is part a here, and sodium bromide, they act very much the same as sodium chloride, but part c here with glucose...